![]() ![]() I suppose XML has too many variants to create a more in depth parser. So as Iterate over each child… I need to check if its ANY of the elements I’m looking for, which I suppose is better than making multiple passes seeking out each child. ![]() I’ve got dozens of attributes by name I want to extract from tens of thousands of xml files. My point being: These Xojo classes can be a bit confusing if you haven’t worked with them.ĭoesn’t seem like I should have to iterate over each child and ask “are you the one with the name I’m looking for?” XMLElement - I’m not sure how this fits together with Nodes and Attributes. XMLAttribute says it represents an attribute node. XMLNode.GetAttributeNode returns an XMLAttribute and not an XMLNode Si el sistema operativo tiene una aplicación adecuada para admitirlo y también existe una asociación entre el archivo y el programa, se debe abrir el archivo. Lo primero que debe hacer es simplemente 'hacer doble clic' en el ícono del archivo XOJOXMLPROJECT que desea abrir. XMLNode.GetAttribute returns a String and not an XMLAttribute. Este problema se puede solucionar fácilmente. Of course I looked at the online documentation, and it seemed to imply that I could request attributes and or nodes by name. I was kinda hoping the parser would lend a little more help. Ok, I hadn’t tried to iterate through all the nodes, and inspect them. Loop through results and display each name attribute ![]() Nodes = root.XQL("//cherry") // Find all cherry nodes in XML Using XQL you would provide the XQL search criteria and then loop through the results: Loop through children and return the node thatĭim nodeCount As Integer = root.ChildCount Public Function FindByNodeName(root As XmlNode, name As String) as XmlNode Xojo is a multi-platform development environment that allows you to create applications for the Mac, Windows and Linux with virtually no specific platform code. It calls the FindByNodeName method which loops through the nodes looking for the one with the name that was passed in. To start with looping, first this code loads up your XML (saved in a constant called kXML):ĭim root As XmlNode = xml.DocumentElementĭim node As XmlNode = FindByNodeName(root, “cherry”) Most of the combinations I’ve tried will compile and execute but they produce nil for docnode (unless I use an index) and I never get docname to receive a value no matter what I’ve tried.Īs Tim and John have said, your options are to loop through the nodes to find the one(s) you want or to use XQL to search for what you want. I’ll keep futzing with it, but I figure the community is chock full of people who have been down this road. I’ve tried about every combination of XmlElement and XmlNode I can think of in conjunction with GetAttribute, and GetAttributeNode to try and find the magic combination that lets me grab specific element values by their name. Ultimately I want the VALUE associated with that specific NAME. However I want to be able to retrieve the element by NAME, not by index, and This seems to retrieve the 0th (First) child of the document. Dim x As FolderItem = GetFolderItem(MyPath) ![]()
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